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Folio - Examples from 'Getting Started' Description Different versions of a portfolio optimization problem. Basic modelling and solving tasks:
Source Files By clicking on a file name, a preview is opened at the bottom of this page. Data Files foliocb.cpp /******************************************************** Xpress-BCL C++ Example Problems =============================== file foliocb.cpp ```````````````` Modeling a MIP problem to perform portfolio optimization. Same model as in foliomip3.cpp. -- Defining an integer solution callback -- (c) 2009-2024 Fair Isaac Corporation author: S.Heipcke, May 2009, rev. Mar. 2011 ********************************************************/ #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cctype> #include "xprb_cpp.h" #include "xprs.h" using namespace std; using namespace ::dashoptimization; #define MAXNUM 15 // Max. number of different assets #define MAXRISK 1.0/3 // Max. investment into high-risk values #define MINREG 0.2 // Min. investment per geogr. region #define MAXREG 0.5 // Max. investment per geogr. region #define MAXSEC 0.25 // Max. investment per ind. sector #define MAXVAL 0.2 // Max. investment per share #define MINVAL 0.1 // Min. investment per share #define DATAFILE "folio10.cdat" // File with problem data #define MAXENTRIES 10000 int NSHARES; // Number of shares int NRISK; // Number of high-risk shares int NREGIONS; // Number of geographical regions int NTYPES; // Number of share types double *RET; // Estimated return in investment int *RISK; // High-risk values among shares char **LOC; // Geogr. region of shares char **SECT; // Industry sector of shares char **SHARES_n; char **REGIONS_n; char **TYPES_n; XPRBvar *frac; // Fraction of capital used per share XPRBvar *buy; // 1 if asset is in portfolio, 0 otherwise #include "readfoliodata.c_" void XPRS_CC print_sol(XPRSprob oprob, void *vp); int main(int argc, char **argv) { int s,r,t; XPRBprob p("FolioMIP3"); // Initialize a new problem in BCL XPRBexpr Risk,Return,Cap,Num; XPRBexpr *MinReg, *MaxReg, *LimSec, LinkL, LinkU; readdata(DATAFILE); // Data input from file // Create the decision variables (including upper bounds for `frac') frac = new XPRBvar[NSHARES]; buy = new XPRBvar[NSHARES]; for(s=0;s<NSHARES;s++) { frac[s] = p.newVar("frac", XPRB_PL, 0, MAXVAL); buy[s] = p.newVar("buy", XPRB_BV); } // Objective: total return for(s=0;s<NSHARES;s++) Return += RET[s]*frac[s]; p.setObj(Return); // Set the objective function // Limit the percentage of high-risk values for(s=0;s<NRISK;s++) Risk += frac[RISK[s]]; p.newCtr(Risk <= MAXRISK); // Limits on geographical distribution MinReg = new XPRBexpr[NREGIONS]; MaxReg = new XPRBexpr[NREGIONS]; for(r=0;r<NREGIONS;r++) { for(s=0;s<NSHARES;s++) if(LOC[r][s]>0) { MinReg[r] += frac[s]; MaxReg[r] += frac[s]; } p.newCtr(MinReg[r] >= MINREG); p.newCtr(MaxReg[r] <= MAXREG); } // Diversification across industry sectors LimSec = new XPRBexpr[NTYPES]; for(t=0;t<NTYPES;t++) { for(s=0;s<NSHARES;s++) if(SECT[t][s]>0) LimSec[t] += frac[s]; p.newCtr(LimSec[t] <= MAXSEC); } // Spend all the capital for(s=0;s<NSHARES;s++) Cap += frac[s]; p.newCtr(Cap == 1); // Limit the total number of assets for(s=0;s<NSHARES;s++) Num += buy[s]; p.newCtr(Num <= MAXNUM); // Linking the variables for(s=0;s<NSHARES;s++) { p.newCtr(frac[s] <= MAXVAL*buy[s]); p.newCtr(frac[s] >= MINVAL*buy[s]); } // Define an integer solution callback XPRSsetcbintsol(p.getXPRSprob(), print_sol, &p); // Solve the problem p.setSense(XPRB_MAXIM); p.mipOptimize(""); char *MIPSTATUS[] = {"not loaded", "not optimized", "LP optimized", "unfinished (no solution)", "unfinished (solution found)", "infeasible", "optimal", "unbounded"}; cout << "Problem status: " << MIPSTATUS[p.getMIPStat()] << endl; return 0; } /**************************Solution printing****************************/ void XPRS_CC print_sol(XPRSprob oprob, void *vp) { int num,s; XPRBprob *bprob; bprob = (XPRBprob *)vp; bprob->beginCB(oprob); XPRSgetintattrib(oprob, XPRS_MIPSOLS, &num); // Get number of the solution bprob->sync(XPRB_XPRS_SOL); // Update BCL solution values cout << "Solution " << num << ": Total return: " << bprob->getObjVal() << endl; for(s=0;s<NSHARES;s++) if(buy[s].getSol()>0.5) cout << " " << SHARES_n[s] << ": " << frac[s].getSol()*100 << "% (" << buy[s].getSol() << ")" << endl; bprob->endCB(); } | |||||||||
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