FICO
FICO Xpress Optimization Examples Repository
FICO Optimization Community FICO Xpress Optimization Home
Back to examples browserPrevious exampleNext example

Minimum weight spanning tree

Description
Six terminals located in different buildings need to be connected. The cost of connecting two terminals is proportional to the distance between them. Determine the connections to install to minimize the total cost.

Further explanation of this example: 'Applications of optimization with Xpress-MP', Section 12.4 'Construction of a cabled network' (g4cable.mos)

spanningtreegr.zip[download all files]

Source Files
By clicking on a file name, a preview is opened at the bottom of this page.
spanningtree_graph.mos[download]

Data Files





spanningtree_graph.mos

(!******************************************************
   Mosel Example Problems
   ======================

   file spanningtree.mos
   `````````````````````
   TYPE:         Minimum weight spanning tree problem
   DIFFICULTY:   3
   FEATURES:     MIP problem, formulation of constraints to exclude subcycles,
                 graphical representation of results
   DESCRIPTION:  Six terminals located in different buildings need to be 
                 connected. The cost of connecting two terminals is 
                 proportional to the distance between them. Determine the 
                 connections to install to minimize the total cost.     
   FURTHER INFO: `Applications of optimization with Xpress-MP', 
                 Section 12.4 `Construction of a cabled network'
   
   (c) 2008 Fair Isaac Corporation
       author: S. Heipcke, 2002, rev. Sep. 2017
*******************************************************!)

model "Cabled network"
 uses "mmxprs", "mmsvg","mmsystem"

 declarations
  NTERM = 6
  TERMINALS = 1..NTERM                  ! Set of terminals to cnct

  DIST: array(TERMINALS,TERMINALS) of integer  ! Distance between terminals

  cnct: array(TERMINALS,TERMINALS) of mpvar ! 1 if direct connection
                                        ! between terminals, 0 otherwise
  level: array(TERMINALS) of mpvar      ! level value of nodes
 end-declarations

 initializations from 'spanningtree.dat'
  DIST
 end-initializations

! Objective: length of cable used
 Length:= sum(s,t in TERMINALS | s<>t) DIST(s,t)*cnct(s,t)

! Number of cnctions
 NumConnect:= sum(s,t in TERMINALS | s<>t) cnct(s,t) = NTERM - 1 

! Avoid subcycle
 forall(s,t in TERMINALS | s<>t) 
  Cycle(s,t):= level(t) >= level(s) + 1 - NTERM + NTERM*cnct(s,t)

! Direct all cnctions towards the root (node 1)
 forall(s in 2..NTERM) Direct(s):= sum(t in TERMINALS | s<>t) cnct(s,t) = 1

 forall(s,t in TERMINALS | s<>t) cnct(s,t) is_binary

! Solve the problem
 minimize(Length)
 
! Solution printing
 writeln("Cable length: ", getobjval)

 write("Connections:")
 forall(s,t in TERMINALS | s<>t)
  write(if(getsol(cnct(s,t))>0, " " + s + "-" + t, "")) 
 writeln

! Solution drawing
 declarations
  X,Y: array(TERMINALS) of integer       ! x-y-coordinates of terminals
 end-declarations
 
 initializations from 'spanningtree.dat'
  [X,Y] as 'POS'
 end-initializations

 minx:=min(t in TERMINALS)X(t)-5; miny:=min(t in TERMINALS)Y(t)-5
 svgsetgraphviewbox(minx, miny,
         max(t in TERMINALS)X(t)+5-minx,max(t in TERMINALS)Y(t)+5-miny)
 
 svgaddgroup("T", "Terminals", SVG_BLACK)
 forall(t in TERMINALS) do
  svgaddpoint(X(t), Y(t))
  svgaddtext(X(t), Y(t)+1, "T"+t)
 end-do
 
 svgaddgroup("C", "Connections", SVG_GREEN)
 forall(s,t in TERMINALS | s<>t)
  if(getsol(cnct(s,t))>0) then
   svgaddtext(round((X(s)+X(t))/2), round((Y(s)+Y(t))/2), 
                string(DIST(s,t)))
   svgaddline(X(t), Y(t), X(s), Y(s))
  end-if

 svgsetgraphscale(5)
 svgsetgraphpointsize(3)

 svgsave("spantree.svg")
 svgrefresh
 svgwaitclose("Close browser window to terminate model execution.", 1)
end-model

Back to examples browserPrevious exampleNext example