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Puzzles and pastimes from the book `Programmation Lineaire' Description The following models implement solutions to the puzzles
published in the book `Programmation Lineaire' by
C. Gueret, C. Prins, and M. Sevaux (Eyrolles 2000, in French).
Each problem is implemented as a MIP and as a CP model.
These models show how to formulate different logical constraints using binary variables (MIP models) or logical constraint relations and global constraints (CP models).
Source Files By clicking on a file name, a preview is opened at the bottom of this page. k3congress_ka.mos (!****************************************************** Mosel Example Problems ====================== file k3congress_ka.mos `````````````````````` Congress puzzle At an international congress taking place on 7-11 August five researchers of different nationality are giving talks, each on a different day. Find out the date and nationality for every researcher from the following information: a) Michael is not Japanese. b) Eric is French and he talks before the 10th. c) Arabinda talks on the 9th. d) The Chinese who is not Hitoshi gives his talk on the 8th, before Michael. e) Hitoshi does his talk after the Indian and before the American. (c) 2008 Fair Isaac Corporation author: S. Heipcke, March 2005 *******************************************************!) model "K-3 Congress (CP)" uses "kalis" declarations DAYS = 7..11 NAMES = {"Arabinda","Eric","Hitoshi","Michael","Zhicheng"} NAT = {"Japanese","French","Chinese","American","Indian"} talkp: array(NAMES) of cpvar ! Choice of day for person p talkn: array(NAT) of cpvar ! Choice of day for nationality n end-declarations forall(p in NAMES) setdomain(talkp(p), DAYS) forall(n in NAT) setdomain(talkn(n), DAYS) ! Every researcher on a different day all_different(talkp) ! Every nationality exactly once all_different(talkn) ! a: Michael is not Japanese talkp("Michael") <> talkn("Japanese") ! b: Eric is French and he talks before the 10th talkp("Eric") = talkn("French") talkp("Eric") <= 9 ! c: Arabinda talks on the 9th talkp("Arabinda") = 9 ! d: The Chinese who is not Hitoshi gives his talk on the 8th, before Michael talkp("Hitoshi") <> talkn("Chinese") talkn("Chinese") = 8 talkp("Michael") >= 9 ! e: Hitoshi does his talk after the Indian and before the American talkp("Hitoshi") >= talkn("Indian") + 1 talkp("Hitoshi") <= talkn("American") - 1 ! Solving and solution printing if cp_find_next_sol then forall(p in NAMES) do write(p," (") day:= getub(talkp(p)) forall(n in NAT) write( if(getub(talkn(n))=day, n, "") ) writeln(") : ", day) end-do else writeln("Problem is infeasible") end-if end-model | ||||||||||||||||||||||||||||||
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