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Els - An economic lot-sizing problem solved by cut-and-branch and branch-and-cut heuristics

Description
The version 'ELS' of this example shows how to implement cut-and-branch (= cut generation at the root node of the MIP search) and 'ELSCut' implements a branch-and-cut (= cut generation at the MIP search tree nodes) algorithm using the cut manager.


Source Files
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ELS.cpp[download]
ELSCut.cpp[download]
ELSManagedCuts.cpp[download]





ELS.cpp

// (c) 2024-2024 Fair Isaac Corporation

/**
 * Economic lot sizing, ELS, problem. Solved by adding (l,S)-inequalities in
 * several rounds looping over the root node.
 *
 * ELS considers production planning over a horizon of T periods. In period t,
 * t=1,...,T, there is a given demand DEMAND[t] that must be satisfied by
 * production prod[t] in period t and by inventory carried over from previous
 * periods. There is a set-up up cost SETUPCOST[t] associated with production in
 * period t. The unit production cost in period t is PRODCOST[t]. There is no
 * inventory or stock-holding cost.
 */

#include <chrono>
#include <iostream>
#include <xpress.hpp>

using namespace xpress;
using namespace xpress::objects;
using xpress::objects::utils::scalarProduct;
using xpress::objects::utils::sum;

using std::chrono::duration_cast;
using std::chrono::steady_clock;

double const EPS = 1e-6;
int const T = 6; /* Number of time periods */

/* Data */
std::vector<double> DEMAND{1, 3, 5, 3, 4, 2};       /* Demand per period */
std::vector<double> SETUPCOST{17, 16, 11, 6, 9, 6}; /* Setup cost / period */
std::vector<double> PRODCOST{5, 3, 2, 1, 3, 1};     /* Prod. cost / period */
std::vector<std::vector<double>>
    D(T, std::vector<double>(T)); /* Total demand in periods t1 - t2 */

/** Create the model in P.
 * @param p      The Xpress Solver instance in which the model is created.
 * @param prod   Array to store the production variables.
 * @param setup  Array to store the setup variables.
 */
void modEls(XpressProblem &p, std::vector<Variable> &prod,
            std::vector<Variable> &setup) {
  for (int s = 0; s < T; s++)
    for (int t = 0; t < T; t++)
      for (int k = s; k <= t; k++)
        D[s][t] += DEMAND[k];

  // Variables
  prod = p.addVariables(T)
             .withType(ColumnType::Continuous)
             .withName([](auto t) { return "prod" + std::to_string(t + 1); })
             .toArray();

  setup = p.addVariables(T)
              .withType(ColumnType::Binary)
              .withName([](auto t) { return "setup" + std::to_string(t + 1); })
              .toArray();

  // Objective: Minimize total cost
  p.setObjective(
      sum(scalarProduct(setup, SETUPCOST), scalarProduct(prod, PRODCOST)),
      ObjSense::Minimize);

  // Constraints

  // Production in period t must not exceed the total demand for the
  // remaining periods; if there is production during t then there
  // is a setup in t
  // for all t in [0,T[
  //     prod[t] <= setup[t] * D[t][T-1]
  p.addConstraints(T,
                   [&](auto t) { return prod[t] <= setup[t] * D[t][T - 1]; });

  // Production in periods 0 to t must satisfy the total demand
  // during this period of time
  // for all t in [0,T[
  //     sum(s in [0,t+1[) prod[s] >= D[0][t]
  p.addConstraints(T, [&](auto t) {
    return sum(t + 1, [&](auto s) { return prod[s]; }) >= D[0][t];
  });
  p.writeProb("ELS.lp", "l");
}

/**
 * Cut generation loop at the top node:
 * solve the LP and save the basis
 * get the solution values
 * identify and set up violated constraints
 * load the modified problem and load the saved basis
 * @param p      The Xpress Solver instance that is populated with the model.
 * @param prod   Production variables.
 * @param setup  Setup variables.
 */
void solveEls(XpressProblem &p, std::vector<Variable> &prod,
              std::vector<Variable> &setup) {
  p.callbacks.addMessageCallback(XpressProblem::console);
  /* Disable automatic cuts - we use our own */
  p.controls.setCutStrategy(XPRS_CUTSTRATEGY_NONE);
  /* Switch presolve off */
  p.controls.setPresolve(XPRS_PRESOLVE_NONE);

  int ncut = 0, npass = 0, npcut = 0;
  steady_clock::time_point starttime = steady_clock::now();
  std::vector<double> sol;

  do {
    p.writeProb("model" + std::to_string(npass) + ".lp");
    npass++;
    npcut = 0;
    // Solve the LP-problem
    p.lpOptimize();
    if (p.attributes.getSolStatus() != SolStatus::Optimal)
      throw std::runtime_error("failed to optimize with status " +
                               to_string(p.attributes.getSolStatus()));
    // Get the solution values:
    sol = p.getSolution();
    // Search for violated constraints:
    for (int l = 0; l < T; l++) {
      double ds = 0.0;
      for (int t = 0; t <= l; t++) {
        if (prod[t].getValue(sol) < D[t][l] * setup[t].getValue(sol) + EPS) {
          ds += prod[t].getValue(sol);
        } else {
          ds += D[t][l] * setup[t].getValue(sol);
        }
      }

      // Add the violated inequality: the minimum of the actual production
      // prod[t] and the maximum potential production D[t][l]*setup[t] in
      // periods 0 to l must at least equal the total demand in periods 0 to l.
      //    sum(t=1:l) min(prod[t], D[t][l]*setup[t]) >= D[0][l]
      if (ds < D[0][l] - EPS) {
        Expression cut = sum(l + 1, [&](auto t) {
          if (prod[t].getValue(sol) < D[t][l] * setup[t].getValue(sol) + EPS)
            return 1.0 * prod[t];
          else
            return D[t][l] * setup[t];
        });
        p.addConstraint(cut >= D[0][l]);
        ncut++;
        npcut++;
      }
    }
    steady_clock::time_point endtime = steady_clock::now();
    std::cout << "Iteration " << npass << ", "
              << duration_cast<std::chrono::milliseconds>(endtime - starttime)
                         .count() *
                     1e-3
              << " sec"
              << ", objective value: " << p.attributes.getObjVal()
              << ", cuts added: " << npcut << " (total " << ncut << ")"
              << std::endl;

    if (npcut == 0)
      std::cout << "Optimal integer solution found:" << std::endl;

  } while (npcut > 0);

  // Print out the solution:
  for (int t = 0; t < T; t++) {
    std::cout << "Period " << (t + 1) << ": prod" << prod[t].getValue(sol)
              << " (demand: " << DEMAND[t] << ", cost: " << PRODCOST[t] << ")"
              << ", setup " << setup[t].getValue(sol) << " (cost "
              << SETUPCOST[t] << ")" << std::endl;
  }
}

int main() {
  XpressProblem prob;
  std::vector<Variable> prod;
  std::vector<Variable> setup;

  modEls(prob, prod, setup);   // Model the problem
  solveEls(prob, prod, setup); // Solve the problem

  return 0;
}

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