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UG - Examples from 'BCL Reference Manual' Description The following examples are discussed in detail in the 'BCL User Guide and Reference Manual':
Source Files By clicking on a file name, a preview is opened at the bottom of this page.
Data Files xbairport.cxx /******************************************************** BCL Example Problems ==================== file xbairport.cxx `````````````````` QCQP problem by Rodrigo de Barros Nabholz & Maria Aparecida Diniz Ehrhardt November 1994, DMA - IMECC- UNICAMP. Based on AMPL model airport.mod by Hande Y. Benson (Source: http://www.orfe.princeton.edu/~rvdb/ampl/nlmodels/ ) (c) 2008 Fair Isaac Corporation author: S.Heipcke, June 2008, rev. Mar. 2011 ********************************************************/ #include <iostream> #include "xprb_cpp.h" #include "xprs.h" using namespace std; using namespace ::dashoptimization; #define N 42 double CX[] = {-6.3, -7.8, -9, -7.2, -5.7, -1.9, -3.5, -0.5, 1.4, 4, 2.1, 5.5, 5.7, 5.7, 3.8, 5.3, 4.7, 3.3, 0, -1, -0.4, 4.2, 3.2, 1.7, 3.3, 2, 0.7, 0.1, -0.1, -3.5, -4, -2.7, -0.5, -2.9, -1.2, -0.4, -0.1, -1, -1.7, -2.1, -1.8, 0}; double CY[] = {8, 5.1, 2, 2.6, 5.5, 7.1, 5.9, 6.6, 6.1, 5.6, 4.9, 4.7, 4.3, 3.6, 4.1, 3, 2.4, 3, 4.7, 3.4, 2.3, 1.5, 0.5, -1.7, -2, -3.1, -3.5, -2.4, -1.3, 0, -1.7, -2.1, -0.4, -2.9, -3.4, -4.3, -5.2, -6.5, -7.5, -6.4, -5.1, 0}; double R[] = {0.09, 0.3, 0.09, 0.45, 0.5, 0.04, 0.1, 0.02, 0.02, 0.07, 0.4, 0.045, 0.05, 0.056, 0.36, 0.08, 0.07, 0.36, 0.67, 0.38, 0.37, 0.05, 0.4, 0.66, 0.05, 0.07, 0.08, 0.3, 0.31, 0.49, 0.09, 0.46, 0.12, 0.07, 0.07, 0.09, 0.05, 0.13, 0.16, 0.46, 0.25, 0.1}; int main(int argc, char **argv) { int i,j; XPRBvar x[N],y[N]; XPRBexpr qe; XPRBctr cobj, c; XPRBprob prob("airport"); // Initialize a new problem in BCL /**** VARIABLES ****/ for(i=0;i<N;i++) x[i] = prob.newVar(XPRBnewname("x(%d)",i+1), XPRB_PL, -10, 10); for(i=0;i<N;i++) y[i] = prob.newVar(XPRBnewname("y(%d)",i+1), XPRB_PL, -10, 10); /****OBJECTIVE****/ // Minimize the total distance between all points // sum(i in 1..N-1,j in i+1..N) ((x(i)-x(j))^2+(y(i)-y(j))^2) qe=0; for(i=0;i<N-1;i++) for(j=i+1;j<N;j++) qe+= sqr(x[i]-x[j])+sqr(y[i]-y[j]); cobj = prob.newCtr("TotDist", qe); prob.setObj(cobj); // Set objective function /**** CONSTRAINTS ****/ // All points within given distance of their target location // (x(i)-CX(i))^2+(y(i)-CY(i))^2 <= R(i) for(i=0;i<N;i++) c = prob.newCtr("LimDist", sqr(x[i]-CX[i])+sqr(y[i]-CY[i]) <= R[i]); /****SOLVING + OUTPUT****/ prob.setSense(XPRB_MINIM); // Choose the sense of optimization /* Problem printing and matrix output: */ /* prob.print(); prob.exportProb(XPRB_MPS, "airport"); prob.exportProb(XPRB_LP, "airport"); */ prob.lpOptimize(""); // Solve the problem cout << "Solution: " << prob.getObjVal() << endl; for(i=0;i<N;i++) { cout << x[i].getName() << ": " << x[i].getSol() << ", "; cout << y[i].getName() << ": " << y[i].getSol() << endl; } return 0; }
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